10-[8-(2x-3)]=2x-5

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Solution for 10-[8-(2x-3)]=2x-5 equation:


Simplifying
10 + -1[8 + -1(2x + -3)] = 2x + -5

Reorder the terms:
10 + -1[8 + -1(-3 + 2x)] = 2x + -5
10 + -1[8 + (-3 * -1 + 2x * -1)] = 2x + -5
10 + -1[8 + (3 + -2x)] = 2x + -5

Combine like terms: 8 + 3 = 11
10 + -1[11 + -2x] = 2x + -5
10 + [11 * -1 + -2x * -1] = 2x + -5
10 + [-11 + 2x] = 2x + -5

Combine like terms: 10 + -11 = -1
-1 + 2x = 2x + -5

Reorder the terms:
-1 + 2x = -5 + 2x

Add '-2x' to each side of the equation.
-1 + 2x + -2x = -5 + 2x + -2x

Combine like terms: 2x + -2x = 0
-1 + 0 = -5 + 2x + -2x
-1 = -5 + 2x + -2x

Combine like terms: 2x + -2x = 0
-1 = -5 + 0
-1 = -5

Solving
-1 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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